Lane's Weighted Creep Theory of Hydraulic Structures

 Lane's Weighted Creep Theory

Lecture-2


Lane's Weighted Creep Theory

This approach assigns different weightages to vertical and horizontal creeps. Lane demonstrated that vertical creep is three times more effective than horizontal creep in minimizing uplift pressure. Vertical creep was assigned a weightage of unity, while horizontal creep was assigned a weightage of 1/3.

The weighted creep length-

N = Sum of all the horizontal contacts and the flat sloping contacts making an angle less than 45o with the horizontal

V = Sum of all vertical contacts and the steep sloping contacts making an angle greater than 45o with the horizontal.

According to Lane's weighted creep theory, structure will be safe if HL/Lw is less than the safe hydraulic gradient 1/C1 for that soil, where, HL is the seepage head, and C1 is Lane’s creep coefficient


The thickness of the floor at any point:

Table: Lane's creep coefficient for different types of soils


Example:

A hydraulic structure on a river as shown in Figure below:

·        Check the floor thickness at points X, Y and Z to counteract the uplift pressure (Gf = 2.4).

·        Check safety against piping if the soil type is coarse sand (C1 = 5).

·        All dimensions are in meter.

Solution:

Lw = 1/3 N + V

N = 1.5 + 5.9 + 2 + 2 + [(5.1)2 + (12.3)2]0.5 +10 + 16 + 1.5 = 52.215 m

V = 1 + (5.2+5.2) + 0.5 + [(0.5)2 + (0.5)2]0.5 + (3.2+3.2) + 1.5 + (4.6+4.6) +1.5 = 31.207 m

Lw = 1/3 * 52.215 + 31.207 = 48.612 m

HL = Difference between U/S Level and D/S = 7.1 m

i = HL/Lw = 0.1461 < 1/5 (0.2), The structure is safe against piping.


Now,

Nx = 1.5 + 5.9 + 2 + 2 = 11.4

Vx = 1 + (5.2+5.2) + 0.5 + [(0.5)2 + (0.5)2]0.5 = 12.61

Lx = 1/3 * 11.4 + 12.61 = 16.41

NY = 1.5 + 5.9 + 2 + 2 + [(5.1)2 + (12.3)2]0.5 = 24.72

VY = 1 + (5.2+5.2) + 0.5 + [(0.5)2 + (0.5)2]0.5 + (3.2+3.2) = 12.61

LY = 1/3 * 24.72 + 12.61 = 20.84

Nz = 1.5 + 5.9 + 2 + 2 + [(5.1)2 + (12.3)2]0.5 +10 + 16 = 50.715  

Vz = 1 + (5.2+5.2) + 0.5 + [(0.5)2 + (0.5)2]0.5 + (3.2+3.2) + 1.5 = 20.507

Lz = 1/3 * 50.715 + 20.507 = 37.412

Using Equation,

h = HL – HL/Lw (l)

hx = HL – HL/Lw (Lx) = 7.1 – 7.1/48.612 (16.41) = 4.703

hY = HL – HL/Lw (LY) = 7.1 – 7.1/48.612 (20.84) = 4.056

hz = HL – HL/Lw (Lz) = 7.1 – 7.1/48.612 (37.412) = 1.636

For checking floor thickness at points X, Y and Z

t =  h/(Gf -1)

tx =  4.703/(2.4-1) =  3.36 > 2 (Not sufficient at this point X)

tY = 4.056/(2.4-1) =  2.90  < 3 (1.5+1.5 = 3) (Sufficient at this point Y)

tz = 1.636/(2.4-1) =  1.17 < 1.5  (Sufficient at this point Z)

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